0x668143c4…385fsent to0x668143c4…385f·#12,761,427·view on Etherscan
Those who were the first 1/sqrt(2) to reveal a number out of those with an ID 1/sqrt(2)^n of the population,
get to reveal 1+n more numbers. n is number of times it has been repeated. Maximum number of votes is 4x population.
The cycles get period/2^n time allocated. Practically, time runs out before log2(population) repetitions. Total votes possible will approximate 4x population.